Which of the following is most active in coag | vedclass

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(A) $Fe(OH)_3$ sol is a positively charged sol. According to the Hardy-Schulze rule,the coagulating power of an electrolyte increases with the increas

Vedclass · Accepted Answer

$K_4[Fe(CN)_6]$

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(A) $Fe(OH)_3$ sol is a positively charged sol. According to the Hardy-Schulze rule,the coagulating power of an electrolyte increases with the increase in the magnitude of the charge on the oppositely charged ion (anion in this case). The anions provided by the electrolytes are: $[Fe(CN)_6]^{4-}$,$SO_4^{2-}$,$Cl^-$,and $NO_3^-$. The magnitude of the charge is highest for $[Fe(CN)_6]^{4-}$. Therefore,$K_4[Fe(CN)_6]$ is the most effective coagulating agent.

Which of the following is most active in coagulating $Fe(OH)_3$ sol,if the sol is made by hydrolysis of $FeCl_3$?

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